Questão 3133769

S=C( \(\overline{A}\) ⋅ B + A ⋅ \(\overline{B}\) ⋅D)

S=C( A ⋅ \(\overline{B}\) + \(\overline{A}\) ⋅ B ⋅D)

S=C(A⋅B+A⋅B⋅ \(\overline{D}\) )

S=C(A⋅ \(\overline{B}\) +A⋅B⋅ \(\overline{D}\) )

S=C(A⋅B+A⋅B⋅D)