Questão 288042

𝐷 = \(\lbrace y\in R|ye-1\rbrace\) e \(f\) ^-1(y)=\(\frac{2y+1}{y-1}\).

𝐷 =\(\lbrace y\ \in R|ye1\rbrace\) e \(f\)^-1(y)= \(\frac{2y+1}{y-1}\) .

𝐷 =\(\lbrace y\ \in R\mid y\ e-1\rbrace\) e \(f\) ^-1(y)=\(\frac{y-1}{y+1}\) .

𝐷 =\(\lbrace y\ \in R\mid y\ e1\rbrace\) e \(f\) ^-1(y)=\(\frac{y-1}{y+1}\) .