Questão 2607194

\(\left \{ \begin{matrix} \frac{2}{3} y = \frac{4}{5}x - 12 \\ -\frac{16}{5}x + \frac{8}{3}y=-36 \end{matrix} \right.\)

\(\left \{ \begin{matrix} 3x - y =-\frac{3}{4} \\ 2x-\frac{6}{5}=y \end{matrix} \right.\)

\(\left \{ \begin{matrix} y = \frac{3}{5}x-2 \\ 2x + y= 1 \end{matrix} \right.\)

\(\left \{ \begin{matrix} -2x-y = -\frac{5}{3} \\ 2y= -4x + \frac{10}{3}\end{matrix} \right.\)