Questão 1703787

\(y\ =\ \frac{x^2}{4}\ -\ x\ +2\)

\(\frac{x^2}{4}-\frac{y^2}{2}=1\)

\(\frac{x^2}{4}+\frac{y^2}{2}=1\)

\(y=x^2-4x\ +\ 8\)

\(\left(x-2\right)^2+\left(y-2\right)^2=0\)