Questão 1665623

\(\left[3^{-2}\ .\ 3^{-2}\right]^2=3^{-8}\)

\(\left[3^{-6}\ :\ 3^2\right]^2=3^8\)

\(\left[3^{-2}\ .\ 3^2\right]^2=1\)

\(\left[3^6\ :\ 3^2\right]^{-2}=3^{-8}\)

\(\left[3^2\ :\ 3^{-2}\right]^{-2}=1\)