Questão 1455564

\(\frac{x^2}{20}\) - \(\frac{y^2}{16}\) = 1

\(\frac{x^2}{16}\) + \(\frac{y^2}{20}\) = 1

\(\frac{x^2}{4}\) + \(\frac{y^2}{25}\) = 1

\(\frac{x^2}{20}\ +\frac{\ y^2}{16}=1\)