Questão 1107630

\(x=\frac{\pi}{12}+\frac{2k\pi-1}{4}\) ou \(x=\frac{2\pi}{12}+\frac{2k\pi-1}{4}\) .

\(x=\frac{\pi}{24}+\frac{2k\pi-1}{4}\) ou \(x=\frac{5\pi}{24}+\frac{2k\pi-1}{4}.\)

\(x=\frac{\pi}{12}+\frac{k\pi}{2}\) ou \(x=\frac{\pi}{12}+\frac{k\pi}{2}.\)

\(x=\frac{\pi}{24}+\frac{k\pi}{2}\) ou \(x=\frac{5\pi}{24}+\frac{k\pi}{2}.\)

\(x=\frac{\pi}{24}+\frac{k\pi-1}{4}.\)