Questão 935560

P(d) = 1 + \(\frac{\log_{10}\left(1⁄d\right)}{1!}+\frac{\log_{10}\left(1⁄d^2\right)}{2!}+...\)

P(d) = 1 + \(\frac{\ln\left(1⁄d\right)}{1!}+\frac{\ln\left(1⁄\left(d-1\right)\right)}{2!}+...\) \(\frac{\ln\left(1⁄d\right)}{1!}+\frac{\ln\left(d-1\right)}{2!}+...\)

P(d) = log₁₀ (1 + 1/d)

P(d) = ln (1 + 1/d)